The number of Faradays required to reduce one mole of Cu2+ to metallic copper is:
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is B 2 Faraday's first law state that," the amount of current passed through the electrode is directly proportional to the number of substances liberated from it."
The reduction of one mole of Cu2+toCu$ can be represented as:
Cu2+2e−→Cu
Since in this reaction, there are two moles of electron involved in this reaction thus the amount of charge required is 2F.