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Question

The number of geometrical isomers in case of a compound with the structure $$CH_{3}- CH= CH- CH= CH- C_{2}H_{5}$$ is:


A
4
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B
3
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C
2
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D
5
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Solution

The correct option is A $$4$$
When a compound has n double bonds and ends of a polyene are different, the number of geometrical isomers = $${ 2 }^{ n }$$
The given compound has two double bonds and two ends are different, $${ CH }_{ 3 }$$ and $${ C }_{ 2 }{ H }_{ 5 }$$.
Therefore the number of geometrical isomers in the given polyene is $${ 2 }^{ n }$$ =$${ 2 }^{ 2 }=4$$
conclusion: hence thje option (A) is correct.

Chemistry

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