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Byju's Answer
Standard XII
Mathematics
nth Term of A.P
The number of...
Question
The number of integers lie in between
1
and
1000
which are divisible by
3
are
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Solution
Given,
3
,
6
,
9
,
⋯
,
996
,
999
We know,
n
=
l
−
a
d
+
1
⋯
(
i
)
where
l
=
999
,
a
=
3
and
d
=
3
Put all these values in eq.
(
i
)
⇒
n
=
999
−
3
3
+
1
⇒
n
=
996
3
+
1
⇒
n
=
332
+
1
=
333
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nth Term of A.P
Standard XII Mathematics
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