Question

The number of integral solutions of 2(x+2) > x^2 + 1 is

1. 2
2. 3
3. 4
4. 5

Answer 1

2x+4 > x^2+1=> x^2-2x-3<0=> (x-1)^2 -4 <0
or (x-1)^2 < 4 => |x-1| < 2
So the solutions are x = -1,0 and 1 only so 3 solutions Answer