Question

The number of integral solutions of $\frac{x+2}{x^2+1}>\frac{1}{2}$ is?

• A. $4$
• B. $5$
• C. $3$
• D. None of these

Answer 1

Answer: (C)

$3$

Given inequality is $\frac{x+2}{x^2+1}>\frac{1}{2}$

$2x+4>x^2+1$
$x^2-2x-3<0$
$(x-3)(x+1)<0$
$+-+$
$-13$
Solutions are;-
$(-1,3)$
Integral solutions are;-
$\{0,1,2\}$
Hence, the answer is $3$