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Question

The number of integral solutions of the equations x210x21x212x+32=(x210x+21x212x+32) is(are)

A
1
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B
2
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C
4
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D
No solution
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Solution

The correct option is D No solution
Given: equation x210x21x212x+32=(x210x+21x212x+32)
To find the number of integral solutions of the equation
Sol: The given equation's absolute part has two parts.
Part 1: +(x210x21x212x+32)=(x210x+21x212x+32)x210x21=(x210x+21)2x220x=0x=10
On back substituting we get no solution.
Part 2: (x210x21x212x+32)=(x210x+21x212x+32)
This gives no solution for x
Hence the number of integral solutions of the given equation is 0

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