The number of ions given by $K_{2} [{P t C l}_{6}]$ in aqueous solution is:

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Solution

The correct option is B 3
The dissociation of $K_{2} [P t C l_{6}]$ in aqueous medium can be represented as:
$K_{2} [P t C l_{6}] (a q .) ⇌ 2 K^{+} (a q .) + [P t C l_{6}]^{2 -} (a q .)$
Hence. total number of ions produced= $2$ potassium ions + $1$ hexachloroplatinate ion= $3$ ions

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[P t (N H_{3})_{6}] C l_{4}

The number of ions formed in aqueous solution by the compound $[C o (N H_{3})_{4} C l_{2}] C l$ is:

[C o (N H_{3})_{6}] C l_{3}

[C o (N H_{3})_{6}] C l_{3}

K_{2} [N i (C N)_{4}] + N H_{3} + 2 K (p o t a s s i u m) \to c o m p l e x (A)

c o m p l e x (A)

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