The number of isomeric forms that are represented by aromatic homocyclic compound C₇H₉N is

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Solution

The correct option is B
5

1. C₆H₅ - CH₂NH₂ 2. C₆H₅ - NH- CH₃ 3,4,5 - C₆H₄(CH₃)NH₂ with o, m & p - position

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The number of isomeric forms that are represented by aromatic homocyclic compound C₇H₉N is

C_{7} H_{9} N

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