The number of lone pairs of electrons on the central atoms of $H_{2} O, S n C l_{2}, P C l_{3}$ and $X e F_{2}$ respectively are :

2, 1, 1, 3

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2, 2, 1, 3

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3, 1, 1, 2

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2, 1, 2, 3

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Solution

The correct option is A 2, 1, 1, 3
The number of lone pairs of electrons on the central atoms of $H_{2} O$ , $S n C l_{2}$ , $P C l_{3}$ and $X e F_{2}$ respectively , are 2, 1, 1, 3.
$H_{2} O$ has 2 bond pairs and 2 lone pairs of electrons. It has bent geometry.
$S n C l_{2}$ has 2 bond pairs and one lone pair of electrons. It has bent geometry.
$P C l_{3}$ has 3 bond pairs and one lone pair of electrons. It has pyramidal geometry.
$X e F_{2}$ has 2 bond pairs and 3 lone pairs of electrons. It has see-saw shape.

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The molecular shapes of $S F_{4}, C F_{4} a n d X e F_{4}$ are

S F_{4}

C F_{4}

X e F_{4}

The number of lone pairs of electrons on SF₄, CF₄ and XeF₄are:

I_{3}^{-}, X e F_{2}, X e F_{4}, H_{2} O, N H_{2}^{-} H_{2} S, H_{2} S O_{4}, N F_{3}

	Molecule	Hybridization	Shape	Number of lone pairs of electrons
$(1)$	$X e O_{3}$	$s p^{3}$	pyramidal	$1$
$(2)$	$X e F_{4}$	$s p^{3} d^{2}$	planar	$3$
$(3)$	$X e F_{2}$	$s p^{3} d$	linear	$2$
$(4)$	$X e O_{4}$	$s p^{3} d^{2}$	pyramidal	$1$

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