Question

The number of milliequivalents of solute present in 250 ml of 0.1 M oxalic acid solution are:

• A. $25$
• B. $50$
• C. $250$
• D. $125$

Answer 1

Answer: (B)

$50$

Oxalic acid, $H_2{C}_2{O}_4$, has 2 acidic hydrogen present.

Normality =Molarity $\times$ acidic hydrogen

No of equivalent $=N\times V$

$\Rightarrow (M\times 2)\times V$

$\Rightarrow 0.1\times 2\times \frac{250}{1000}$

$=\frac{50}{1000}$

No of milli equivalent $=50$

Hence, option B is correct.