Question

The number of mole of ferrous oxalate oxidized by one mole of $KMn{O}_4$ is

• A. $\frac{1}{5}$
• B. $\frac{3}{5}$
• C. $\frac{2}{3}$
• D. $\frac{5}{3}$

Answer 1

The correct option is D $\frac{5}{3}$

Reaction:
$Fe{C}_2{O}_4+KMn{O}_4\to M{n}^{+2}+F{e}^{+3}+C{O}_2$
+2 +3 +7 +2 +3 +4
So, one mole of $KMn{O}_4$ oxidises $5/3$ mole of ferrous oxalate.