Question

The number of molecule at NTP in 1 ml of an ideal gas will be

• A. $6\times {10}^{23}$
• B. $2.69\times {10}^{19}$
• C. $2.69\times {10}^{23}$
• D. None of these

Answer 1

The correct option is B $2.69\times {10}^{19}$

$\because$ 22400 ml at NTP has $6.023\times {10}^{23}$ molecule
$\therefore$ 1 ml at NTP has $=\frac{6.023\times {10}^{23}}{22400}$
$=0.0002688\times {10}^{23}=2.69\times {10}^{19}$