The number of molecule in $4.25$ g of $N H_{3}$ is:

1.505 \times 10^{23}

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3.01 \times 10^{23}

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6.02 \times 10^{23}

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none of these

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Solution

The correct option is A $1.505 \times 10^{23}$
Molar mass $N H_{3}$ = 14+3 = 17g/mol
Given mass = 4.25g
No of moles= $\frac{g i v e n m a s s}{m o l a r m a s s}$
No of moles = 4.25/17 = 0.25 mol of $N H_{3}$
1 mol of $N H_{3}$ contains $6.022 \times 10^{23}$ molecules
0.25 mol $N H_{3}$ contains $0.25 \times$ $6.022 \times 10^{23}$ = $1.5055 \times$ $10^{23}$ molecules

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Similar questions

THe number of molecules in 4.25 g of ammonia is:
(a) $1.0 \times 10^{23}$ (b) $1.5 \times 10^{23}$
(c) $2.0 \times 10^{23}$ (d) $3.5 \times 10^{23}$

The number of molecules present in $4.25 g r a m s$ of $N H_{3}$ is approximately:

The number of molecules in 16.0g of oxygen is

6.02 \times 10^{23}

3.01 \times 10^{23}

6.02 \times 10^{23}

3.01 \times 10^{23}

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