The number of molecules in 16-0 g of oxygen isA- 6-02 - 1023- 6-02 - 10-23- 3-01 - 10-23D- 3-01 - 1023

The correct option is D 3.01 × 10^2332 g or 1 mole of O_2 = 6.023 × 10^23 So, 16 g of O_2 = 6.023 × 10^23× 16/32 = 3.01 × 10^23 molecules ...

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Atomic Weight and Atomic Mass Unit

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Question

The number of molecules in 16.0g of oxygen is

6.02 \times 10^{23}

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6.02 \times 10^{- 23}

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3.01 \times 10^{- 23}

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3.01 \times 10^{23}

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