The number of molecules in 4-25 g of ammonia is approximatelyA- 0-5 - 1023B- 1-5 - 1023C- 3-5 - 1023D- 2-5 - 1023

The correct option is B 1.5X1023Calculate using mole concept ...

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The number of molecules in 4.25 g of ammonia is approximately

0.5X10²³

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1.5X10²³

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3.5X10²³

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2.5X10²³

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N H_{3}

THe number of molecules in 4.25 g of ammonia is:
(a) $1.0 \times 10^{23}$ (b) $1.5 \times 10^{23}$
(c) $2.0 \times 10^{23}$ (d) $3.5 \times 10^{23}$

N H_{3}

4.25 g r a m s

N H_{3}

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