The number of molecules in $4.25$ g of $N H_{3}$ is :

1.505 \times 10^{23}

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3.01 \times 10^{23}

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6.02 \times 10^{23}

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none of these

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Solution

The correct option is A $1.505 \times 10^{23}$
As $17$ g of $N H_{3}$ has $1$ mol.

Number of moles in $4.25 g = \frac{4.25}{17}$

Number of molecules = $\frac{4.25}{17} \times N_{A}$ $= 1.505 \times 10^{23}$

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