The number of molecules in 89.6 L of a gas at STP are:

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Solution

The correct option is D

22.4 L of a gas at STP = $6.022 \times 10^{23}$ molecules
89.6L of a gas at STP = $\frac{6.022 \times 10^{23} \times 89.6}{22.4} = 4 \times 6.022 \times 10^{23}$ molecules.

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The number of molecules in 89.6 L of a gas at STP are:

The correct option is D 22.4 L of a gas at STP = 6.022×1023 molecules 89.6L of a gas at STP = 6.022×1023×89.622.4=4×6.022×1023 molecules.

The correct option is D

22.4 L of a gas at STP = $6.022 \times 10^{23}$ molecules
89.6L of a gas at STP = $\frac{6.022 \times 10^{23} \times 89.6}{22.4} = 4 \times 6.022 \times 10^{23}$ molecules.