The number of molecules present in $18 c m^{3}$ of water is:
(density of water is $1 c m^{3}$ )

3.011 \times 10^{23}

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6.022 \times 10^{23}

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3.011 \times 10^{22}

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6.022 \times 10^{22}

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Solution

The correct option is B $6.022 \times 10^{23}$
density of water $= 1 g / c m^{3}$
man of water $= 1 \times 8 = 1 g$
number of mole $= \frac{18}{18} = m o l e$
no. of molecular $= 6.022 \times 10^{23}$

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The number of molecules present in 18 cm3 of water is: (density of water is 1 cm3)

The correct option is B 6.022×1023density of water =1 g/cm3man of water =1×8=1gnumber of mole =1818=moleno. of molecular =6.022×1023

The number of molecules present in $18 c m^{3}$ of water is:
(density of water is $1 c m^{3}$ )

The correct option is B $6.022 \times 10^{23}$
density of water $= 1 g / c m^{3}$
man of water $= 1 \times 8 = 1 g$
number of mole $= \frac{18}{18} = m o l e$
no. of molecular $= 6.022 \times 10^{23}$