The number of molecules present in 4.25 grams of NH3 is approximately:
1 X 1023
1.5 X 1023
2 X 1023 NH3
6.02 X 1023
4.2517 × 6.022 × 1023 =1.50 × 1023 (approximately)
The number of atoms present in 4.25 grams of NH3 is approximately
The number of atoms present in 4.25 grams of NH3 is pproximately
The number of atoms present in 4.25 grams of NH3 is approximately________.
THe number of molecules in 4.25 g of ammonia is: (a) 1.0×1023 (b) 1.5×1023 (c) 2.0×1023 (d) 3.5×1023
The number of atoms present in 4.25 g of NH3 is approximately.
a) 1×1023
b) 1.5×1023
c) 0.25×1023
d) 6.02×1023