The number of molecules present in $4.4$ g of $C O_{2}$ gas is:

6.022 \times 10^{23}

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5.022 \times 10^{23}

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6.022 \times 10^{24}

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6.022 \times 10^{22}

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Solution

The correct option is D $6.022 \times 10^{22}$
1 mole of $C O_{2}$ have $6.022 \times 10^{23}$ molecules.

Weight of one 1 mole of $C O_{2}$ = 44g(molar mass).
Number of moles = $\frac{g i v e n m a s s}{m o l a r m a s s}$ .
Number of moles of $C O_{2}$ in 4.4 g = $\frac{4.4}{44} = 0.1$ .

So, number of molecules in 4.4g of $C O_{2}$ = $\frac{6.022 \times 10^{23}}{44} \times 4.4 = 6.023 \times 10^{22}$ .

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Similar questions

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

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Q. The number of molecules in 89.6 L of a gas at STP are

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

(a) $12.044 \times 10^{20}$ molecules (b) $6.022 \times 10^{23}$ molecules

How many molecules are present in 9g of water?

One mole of oxygen gas at STP is equal to...........

(a) $6.022 \times 10^{23}$ molecules of oxygen

(b) $6.022 \times 10^{23}$ atoms of oxygen

(d) 32 g of oxygen

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The number of molecules present in 4.4 g of CO2 gas is:

The correct option is D 6.022×10221 mole of CO2 have 6.022×1023 molecules.Weight of one 1 mole of CO2 = 44g(molar mass).Number of moles = given massmolar mass.Number of moles of CO2 in 4.4 g = 4.444=0.1.So, number of molecules in 4.4g of CO2 = 6.022×102344×4.4=6.023×1022.

The number of molecules present in $4.4$ g of $C O_{2}$ gas is: