The number of molecules present in $8$ grams of oxygen gas are:

6.022 \times 10^{23}

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3.011 \times 10^{23}

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12.044 \times 10^{23}

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1.55 \times 10^{23}

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Solution

The correct option is D $1.55 \times 10^{23}$
The molar mass of oxygen gas is 32 g/mol.

$n = \frac{8 g}{32 g / m o l} = 0.25 m o l$

$n = \frac{N_{a}}{6.022 \times 10^{23}}$

$N_{a} = 0.25 \times 6.022 \times 10^{23} = 1.55 \times 10^{23}$ molecules

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The number of molecules present in 8 grams of oxygen gas are:

The correct option is D 1.55×1023The molar mass of oxygen gas is 32 g/mol.n=8g32g/mol=0.25 moln=Na6.022×1023Na=0.25×6.022×1023=1.55×1023 molecules

The number of molecules present in $8$ grams of oxygen gas are:

The correct option is D $1.55 \times 10^{23}$
The molar mass of oxygen gas is 32 g/mol.

$n = \frac{8 g}{32 g / m o l} = 0.25 m o l$

$n = \frac{N_{a}}{6.022 \times 10^{23}}$

$N_{a} = 0.25 \times 6.022 \times 10^{23} = 1.55 \times 10^{23}$ molecules