The number of moles of electrons present in 3-0115 - 1024 particles of CO is-

Moles of CO = number of particlesAvogadro's number = 3.0115 × 10^246.023 × 10^23 = 5 Number of electrons present in 1 molecule of CO = 6+8=14 Number of moles of ...

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Standard XII

Chemistry

Mole Concept

The number of...

Question

The number of moles of electrons present in $3.0115 \times 10^{24}$ particles of $C O$ is:

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Solution

Moles of $C O = \frac{number of particles}{Avogadro's number} = \frac{3.0115 \times 10^{24}}{6.023 \times 10^{23}} = 5$
Number of electrons present in 1 molecule of $C O = 6 + 8 = 14$
Number of moles of electrons present in 5 mol of $C O = 14 \times 5 = 70$

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The number of moles of electrons present in 3.0115×1024 particles of CO is:

Moles of CO=number of particlesAvogadro's number=3.0115×10246.023×1023=5 Number of electrons present in 1 molecule of CO=6+8=14 Number of moles of electrons present in 5 mol of CO=14×5=70

The number of moles of electrons present in $3.0115 \times 10^{24}$ particles of $C O$ is:

Moles of $C O = \frac{number of particles}{Avogadro's number} = \frac{3.0115 \times 10^{24}}{6.023 \times 10^{23}} = 5$
Number of electrons present in 1 molecule of $C O = 6 + 8 = 14$
Number of moles of electrons present in 5 mol of $C O = 14 \times 5 = 70$