Question

The number of moles of $F{e}_2{O}_3$ formed when $0.5$ moles of $O_2$ and $0.5$ moles of Fe are allowed to react is:

• A. $0.25$
• B. $0.5$
• C. $0.333$
• D. $0.125$

Answer 1

The correct option is A $0.25$

The reaction is given below;

$4Fe+3O_2\to 2F{e}_2{O}_3$

Fe is the limiting reagent in this reaction. Limiting reagent decides the amount of product formed.

Therefore, $4$ moles of Fe produce $2$ moles of $F{e}_2{O}_3$.

Thus, $0.5$ moles of Fe will produce $0.25$ moles of $F{e}_2{O}_3$.