The number of moles of $F e^{2 +}$ that can be oxidized by one mole of $K M n O_{4}$ in acidified solution is___________.

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Solution

Reaction:
$2 K M n O_{4} + 10 F e S O_{4} + 8 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O$
So, the number of moles of $F e^{2 +}$ that can be oxidized by one mole of $K M n O_{4}$ in acidified solution is 5.

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The number of moles of Fe2+ that can be oxidized by one mole of KMnO4 in acidified solution is___________.

Reaction:2KMnO4+10FeSO4+8H2SO4→5Fe2(SO4)3+K2SO4+2MnSO4+8H2OSo, the number of moles of Fe2+ that can be oxidized by one mole of KMnO4 in acidified solution is 5.

The number of moles of $F e^{2 +}$ that can be oxidized by one mole of $K M n O_{4}$ in acidified solution is___________.

Reaction:
$2 K M n O_{4} + 10 F e S O_{4} + 8 H_{2} S O_{4} \to 5 F e_{2} (S O_{4})_{3} + K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O$
So, the number of moles of $F e^{2 +}$ that can be oxidized by one mole of $K M n O_{4}$ in acidified solution is 5.