You visited us 1 times! Enjoying our articles? Unlock Full Access!

Ideal Gas Equation

The number of...

Question

The number of moles of $F e_{2} O_{3}$ formed when $5.6$ of $O_{2}$ reacts with $5.6 g m$ of $F e$ is :

0.125

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.01

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.05

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $0.05$
Balanced Reaction is:
$4 F e + 3 O_{2} \to 2 F e_{2} O_{3}$

$5.6 g m$ $5.6 g m$

$(\frac{5.6}{56})$ $(\frac{5.6}{32})$

$0.1 m o l e 0.175 m o l e$

$4 m o l e s F e$ reacts with $3 m o l e s$ of $O_{2}$ .

$∴$ 0.1 mole $F e$ reacts with $\frac{3 \times 0.1}{4} m o l e s O_{2}$

Here, Fe is limiting reagent.

4 moles of $F e$ form 2 moles of $F e_{2} O_{3}$

Mole of $F e_{2} O_{3}$ formed by 0.1 mole $F e = \frac{2}{4} \times 0.10$
$= 0.05 m o l e$

The correct option is $^{'} C^{'}$ .

Suggest Corrections

Similar questions

F e_{2} O_{3}

0.5

O_{2}

0.5

The number of moles of $F e_{2} O_{3}$ formed when $0.5 m o l e s$ of $O_{2}$ and $0.5 m o l e s$ of $F e$ are allowed to react are

F e_{2} O_{3}

F e S_{2}

O_{2} .

4 F e S_{2} + 11 O_{2} \to 2 F e_{2} O_{3} + 8 S O_{2}

F e_{2} O_{3}

F e S_{2}

O_{2} .

4 F e S_{2} + 11 O_{2} \to 2 F e_{2} O_{3} + 8 S O_{2}

F e

O_{2}

F e O

F e_{2} O_{3}

Join BYJU'S Learning Program