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Question

The number of moles of $$KMnO_4$$ that are needed to react completely with one mole of ferrous oxalate in acidic solution is:


A
3/5
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B
2/5
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C
4/5
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D
1
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Solution

The correct option is A 3/5
$$3KMnO_4$$ + $$5FeC_2O_4$$ + $$H^+$$ $$\rightarrow$$ $$5Fe^{3+}$$ + $$10CO_2$$ + $$3Mn^{2+}$$ + $$3K^+$$ + $$H_2O$$,
If 3 moles of $$KMnO_4$$ react with 5 moles of $$FeC_2O_4$$, then, with one mole of $$FeC_2O_4$$, $$\dfrac{3}{5}$$ of $$KMnO_4$$ will react.

Chemistry

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