Question

The number of neutrons in the parent nucleus which gives $N^{14}$ on $\beta$ -emission is:

• A. 7
• B. 14
• C. 6
• D. 8

Answer 1

The correct option is D 8

${}_6{X}^{14}{\stackrel{\beta }{\to }}_{6+1}{N}^{14}$

In ${}_6{X}^{14}$, no. of neutrons $14-6=8$