Question

The number of nodal planes present in ${\sigma }^{\ast }s$ antibonding orbitals is:

• A. $1$
• B. $2$
• C. $0$
• D. $3$

Answer 1

The correct option is A $1$

The number of nodal planes present in ${\sigma }^{\ast }s$ anti-bonding orbitals is $1$. The ${\sigma }^{\ast }$ orbital has a nodal plane that is between the nuclei and perpendicular to the inter-nuclear axis. Hence, option $A$ is correct.