The number of optical isomers of the compound $C H_{3} - C H (B r) - C H (B r) - C O O H$ is :

0

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1

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3

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4

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Solution

The correct option is A $4$
The given compound has 4 isomers as it contains 2 chiral carbons.

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\begin{matrix} C H_{3} | H & - & C & - & O H | C O O H \end{matrix}

C H_{3} C H (O H) C O O H

C H_{3} - C H (B r) - C H_{3} a l c . K O H - ----- \to A H B r - ---- \to p e r o x i d e B N a I - --- \to a c e t o n e C

C

C H_{3} - C H (B r) - C H_{3}

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