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Atoms and Molecules

The number of...

Question

The number of oxygen atoms in 1 mol of the tetrahydrocannabinol is _______.
where, $N_{A} = 6.023 \times 10^{23}$

2 N_{A}

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N_{A}

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3 N_{A}

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4 N_{A}

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Solution

The correct option is B $2 N_{A}$
Molecular formula of tetrahydrocannabinol $= C_{21} H_{30} O_{2}$

In 1 molecule of compound number of oxygen atom $= 2.$

Number of oxygen atoms in 1 mole of tetrahydrocannabinol $= 2 N_{A}$

Hence, the correct option is $(A)$ .

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N a

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[A s s u m e c h l o r i n e i s a n i d e a l g a s a t S T P R = 0.083 L b a r m o l^{- 1} K^{- 1}, N_{A} = 6.023 \times 10^{23}]

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