Question

The number of oxygen atoms present in $2$ moles of a compound, which consists of a bivalent metal and a perchlorate ion is:

• A. $4$$N_A$
• B. $6$$N_A$
• C. $8$$N_A$
• D. $16$$N_A$

Answer 1

Answer: (D)

$16$$N_A$

The metal ($M^{2+}$) & perchlorate ion ($Cl{O}_4^{-}$) combine to form a compound with the formula $M(Cl{O}_4{)}_2$

$\therefore$ No. of oxygen atoms in $1$ mole of $M(Cl{O}_4{)}_2$ $=8N_A$

No. of atoms in $2$ moles of $M(Cl{O}_4{)}_2$ $=8N_A\times 2=16N_A$