(d) r ! n − 3Cr − 3
Here, we have to permute n things of which 3 things are to be included.
So, only the remaining (n3) things are left for permutation, taking (r3) things at a time. This is because 3 things have already been included.
But, these r things can be arranged in r! ways.
∴ Total number of permutations = r ! n − 3Cr − 3