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Question

The number of permutations of n different things taking r at a time when 3 particular things are to be included is
(a) n − 3Pr − 3

(b) n − 3Pr

(c) nPr − 3

(d) r ! n − 3Cr − 3

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Solution

(d) r ! n − 3Cr − 3
Here, we have to permute n things of which 3 things are to be included.
So, only the remaining (n-3) things are left for permutation, taking (r-3) things at a time. This is because 3 things have already been included.
But, these r things can be arranged in r! ways.
∴ Total number of permutations = r ! n − 3Cr − 3

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