Question

The number of $\pi$ bonds in a nitrogen atom is .

• A. 1
• B. 2
• C. 3

Answer 1

The correct option is B 2

Let's think about the question.

First, we have to find out the bond order of MOT.

As we know how to draw MOT of $N_2$.

Because for bonding, we only need valance electrons

Now, bond order = $\frac{1}{2}$ [Number of bonding electrons - Number of anti-bonding electrons]
$=\frac{1}{2}[8-2]=3$

Therefore, there will be three bonds between two nitrogen atoms.

Out of these three bonds, 2 bonds will be $\pi$ bonds (formed by $2p_x\&2p_y$) and one will $\sigma$ bond (formed by $2p_z$).

$\therefore$ The number of bonds in nitrogen molecule is 2.

Answer $⟶$ 2 bonds.