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Question

The number of real roots of 32x2āˆ’7x+7=9 is :

A
2
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B
1
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C
4
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D
0
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Solution

The correct option is A 2

32x27x+7=932x27x+7=32

2x27x+7=22x27x+5=0

Here Discriminant =(7)24(2)(5)=4940=9> 0

Hence, the given equation has two real roots.


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