The number of real solutions of $e^{x} = | x - 1 |$ is

1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1$
The number of real solutions of $e^{x} = | x - 1 |$ is
let $y = e^{x}$
$∴$ $y = e^{x} = | x - 1 |$
If $x = 0$
$y$ becomes $1$
$y = e^{0} = | 0 - 1 | = 1$
There is only 1 solution for $e^{x} = | x - 1 |$
i.e., when $x = 0$

No. of real solutions is $1$

Suggest Corrections

Similar questions

2 | x |^{2} - 5 | x | + 2 = 0

1 + | e^{x} - 1 | = e^{x} (e^{x} - 2)

c o s {s i n^{- 1} \frac{1}{3} + c o s^{- 1} x} = 0

1 + | e^{x} - 1 | = e^{x} (e^{x} - 2)

2 l o g_{2} l o g_{2} x + l o g_{\frac{1}{2}} l o g_{2} (2 \sqrt{2} x) = 1

Join BYJU'S Learning Program