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Question

The number of real solutions of the equation (15+414)t+(15414)t=30, where t=x22x are

A
0
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B
2
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C
4
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D
6
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Solution

The correct option is C 4

For the equation, (15414)t+(15+414)t=30 to be true,

t=±1

Now, t=x22|x|

x22|x|=±1

x22|x|+1=0

(|x|1)2=0

x=±1 and x22|x|1=0

|x|=2±4+42

|x|=1±2

Hence, 4 values.


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