The number of real solutions of the equation $2^{3 x^{2} - 7 x + 4} = 1$ is:

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infinitely many

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Solution

The correct option is B 2
$2^{3 x^{2} - 7 x + 4} = 1 = 2^{\circ} \Rightarrow 3 x^{2} - 7 x + 4 = 0 \Rightarrow 3 x^{2} - 3 x - 4 x + 4 = 0 \Rightarrow 3 x (x - 1) - 4 (x - 1) = 0 \Rightarrow x = 1 o r x = \frac{4}{3} ∴ x = 1, \frac{4}{3}$

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