The number of revolutions made by electron in one second in the $2^{n d}$ Bohr orbit of hydrogen atom is:

$6.29 \times 10^{12}$

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$5.29 \times 10^{13}$

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$2.39 \times 10^{15}$

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$8.23 \times 10^{14}$

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Solution

The correct option is D
$8.23 \times 10^{14}$

If V is the speed of moving electron in the said Bohr orbit then the number of revolutions made by electron in one second would be

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The number of revolutions made by electron in one second in the 2nd Bohr orbit of hydrogen atom is:

The correct option is D 8.23×1014 If V is the speed of moving electron in the said Bohr orbit then the number of revolutions made by electron in one second would be

The number of revolutions made by electron in one second in the $2^{n d}$ Bohr orbit of hydrogen atom is:

The correct option is D
$8.23 \times 10^{14}$

If V is the speed of moving electron in the said Bohr orbit then the number of revolutions made by electron in one second would be