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Question

The number of silicon atoms per m3is 5 × 1028. This is dopedsimultaneously with 5 × 1022 atoms per m3of Arsenic and 5 × 1020per m3atoms of Indium. Calculate the number of electrons and holes.Given that ni= 1.5 × 1016 m–3. Is the material n-type or p-type?

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Solution

Number of silicon atoms, N S =5× 10 28 atoms/m 3 .

It is doped with arsenic and indium. Number of arsenic atoms, N As =5× 10 22 atoms/m 3 .

Number of indium atoms, N In =5× 10 22 atoms/m 3 .

It is given that the number of thermally generated electrons, n i =1.5× 10 20 atoms/m 3 .

The number of electrons in the semiconductor will be difference of the number of electrons in arsenic and number of thermally generated electrons.

n e =5× 10 22 1.5× 10 16 = 10 22 ( 51.5× 10 6 ) 4.99× 10 22

Let n h be the number of holes in the semiconductor.

The relation between the number of holes and number of electrons in a semiconductor at thermal equilibrium is given by,

n e n h = ( n i ) 2

Substitute the values in the above formula and find the value of number of holes.

n h = ( n i ) 2 n e = ( 1.5× 10 16 ) 2 4.99× 10 22 =4.51× 10 9

Thus, number of holes is 4.51× 10 9 and number of electrons is 4.99× 10 22 .

Since the number of electrons in the semiconductor is higher than the number of holes, the material is an n-type semiconductor.


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