Question

The number of sodium atoms in $2$ moles of sodium ferrocyanide is:

• A. $12\times {10}^{23}$
• B. $26\times {10}^{23}$
• C. $34\times {10}^{23}$
• D. $48\times {10}^{23}$

Answer 1

The correct option is D $48\times {10}^{23}$

Formul of sodium ferrocyanide $N{a}_4\left[Fe{\left(CN\right)}_6\right]$ of suggest that it has four sodium atoms.

Number of $Na$ atoms

$=$ Number of moles $\times$ number of atoms per molecule $\times$ Avogadro number

$=2\times 4\times 6.023\times {10}^{23}$

$=48\times {10}^{23}$

Hence, option $D$ is correct.