The correct option is B 1
Let radius be 'r' and height be 'h' of the solid cone, where r and h are integers
Volume = surface area
13πr2h=πrl+πr2 [l=√r2+h2]
⇒rh−3r=3√r2+h2
Squaring both sides,
⇒r2h2+9r2−6r2h=9(r2+h2)⇒r2h2−9h2=6r2h⇒h2(r2−9)=6r2h⇒h=6r2r2−9=6+54r2−9⇒r2=9+54h−6
since r and h are integer, so r2 will be perfect square,
for r2=16,h≠Ir2=25,h≠Ir2=36,h=8r2=49,h≠I
Hence there is only 1 possible integer values of r and h.