The number of solution of the simultaneous algebraic equations $y = 3 x + 3$ and $y = 3 x + 5$ is

zero

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infinite

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Solution

The correct option is A zero
Given simultaneous algebraic equations
$- 3 x + y = 3$ and
$- 3 x + y = 5$
Mathematically it is a contradiction.
So no solution exist.

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Similar questions

(x, y)

{log}_{1 / 3} (x + y) + {log}_{3} (x - y) = 2

2^{y^{2}} = 512^{x + 1}

\frac{2 x - 1}{3} = \frac{y + 6}{5} = \frac{3 x - y}{7}

(x, y)

{log}_{1 / 3} (x + y) + {log}_{3} (x - y) = 2

2^{y^{3}} = 512^{x + 1}

x = 2, y = 1

3 x - 2 y = 4

2 x + y = 5

2 x + y = 5, 3 x - y = 5

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