The number of solutions of the equation x -7- x -3-3-7- x -3 isA- 0B- 1C- 2D- 3

The correct option is A 0x 7x 3=3 7x 3 For the given equation to be defined, x 3 Now, solving the equation x 7x 3=3 7x 3 ⇒ x = 3 But we cannot take x= 3 as a v ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Quadratic Equation

The number of...

Question

The number of solution(s) of the equation $x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3}$ is

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0$
$x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3}$
For the given equation to be defined,
$x \neq 3$
Now, solving the equation
$x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3} \Rightarrow x = 3$
But we cannot take $x = 3$ as a valid solution.
Hence, the given equation has no solution.

Suggest Corrections

Similar questions

Q. Number of solutions of the equation

| x - 1 | + | x - 2 | + | x - 3 | = 7

The number of solutions of ${log}_{3} (x - 3) = 4 - x$ is

The number of solutions of $\sqrt{3 x^{2} + x + 5} = x - 3$ is

Q. Number of values of

x

, satisfying the equation

\sqrt{(x + 8) + 2 \sqrt{(x + 7)}} + \sqrt{(x + 1) - \sqrt{x + 7}} = 4,

Q. Number of solutions of the equation tan x + sec x = 2 cos x lying in the interval [0, 2π] is
(a) 0
(b) 1
(c) 2
(d) 3

Join BYJU'S Learning Program

The number of solution(s) of the equation x−7x−3=3−7x−3 is

The correct option is A 0x−7x−3=3−7x−3 For the given equation to be defined, x≠3 Now, solving the equation x−7x−3=3−7x−3⇒x=3 But we cannot take x=3 as a valid solution. Hence, the given equation has no solution.

The number of solution(s) of the equation $x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3}$ is

The correct option is A $0$
$x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3}$
For the given equation to be defined,
$x \neq 3$
Now, solving the equation
$x - \frac{7}{x - 3} = 3 - \frac{7}{x - 3} \Rightarrow x = 3$
But we cannot take $x = 3$ as a valid solution.
Hence, the given equation has no solution.