The number of solutions of √3x2+x+5=x−3 is
0
Note that we must have 3x2+x+5≥0 and x−3≥0 or x≥3
√3x2+x+5=x−3...(1)
Squaring both sides of (1), we get
3x2+x+5=x2−6x+9⇒2x2+7x−4=0⇒(2x−1)(x+4)=0⇒x=12,−4
None of these satisfy the inequality x≥3 Thus, (1) has no solution.