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Byju's Answer
Standard XII
Mathematics
Period of Trigonometric Ratios
The number of...
Question
The number of solutions of the equation
(
|
sin
x
|
−
1
)
(
5
|
sin
x
|
−
1
)
=
0
in
[
0
,
2
π
]
is
A
3
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B
4
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C
5
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D
6
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Solution
The correct option is
D
6
(
|
sin
x
|
−
1
)
(
5
|
sin
x
|
−
1
)
=
0
⇒
|
sin
x
|
=
1
or
|
sin
x
|
=
1
5
So, plotting the graphs of
y
=
|
sin
x
|
,
y
=
1
,
y
=
1
5
∴
From the above graph, we conclude that the total number of solutions of the given equation is
6.
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0
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