Question

The number of stereoisomeric forms in which $\left[Co\right(N{H}_3{)}_{4}C{l}_2{]}^{+}$ ion can occur is:

• A. $2$
• B. $3$
• C. $4$
• D. $1$

Answer 1

The correct option is A $2$

Total $2$ stereoisomers are possible for $\left[Co\right(N{H}_3{)}_{4}C{l}_2{]}^{+}$. Out of two geometrical isomers, one will be cis form and other will be trans form.