Question

The number of structural alcoholic isomers for $C_4{H}_{10}O$ is:

• A. $2$
• B. $3$
• C. $4$
• D. $1$

Answer 1

The correct option is C $4$

The four alcoholic isomers of the $C_4{H}_{10}O$ are

$H_{3}C-C{H}_2-C{H}_2-C{H}_2-OH$

$H_{3}C-C{H}_2-\underset{C{H}_3}{\underset{|}{C}H}-OH$

$H_{3}C-\underset{C{H}_3}{\underset{|}{C}H}-C{H}_2-OH$

$H_{3}C-\stackrel{C{H}_3}{\stackrel{|}{\underset{C{H}_3}{\underset{|}{C}}}-}OH$

Hence, the correct option is $C$