The number of terms between 105 and 1000 which are divisible by 7 is
A
142
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B
128
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C
127
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D
None of these
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Solution
The correct option is C127 Clearly, the numbers between 105 and 1000 which are divisible by 7 are 112,119,126,...,994. This is an AP with first term a=112, common difference d=7 and last term l=994. Let there be n terms in this AP. Then, an=994⇒a+(n−1)d