Question

The number of unpaired electrons expected for the complex ion $\left[Cr\right(H_{2}O{)}_6{]}^{2+}$ is :

• A. 2
• B. 3
• C. 4
• D. 5

Answer 1

The correct option is C 4

$C{r}^{2+}-\left[Ar\right]3d^4$ So the no. of unpaired electrons will be 4. Since $H_{2}O$ is not strong field ligand it won't pair the unpaired electrons.