The number of unpaired electrons in Co in the complex ion ${[C o {(C_{2} O_{4})}_{3}]}^{3 -}$ is [Atomic number of $C o = 27$ ]

4

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3

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Z e r o

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5

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Solution

The correct option is A $4$

$[C O (C_{2} O_{4})_{3}]^{3 -}$
Charge of oxalate ion is $- 2$
Charge on $C O$ is $C O + (- 2) = - 3$
$C O = + 3$
Hybridisation of $C O^{3 +}$ is (Refer to Image 1)
$C_{2} O_{4}^{2 -}$ is weal field ligand so forms high spin complex
(Refer to Image 2)
Number of unpaired electrons= $4$ .

Suggest Corrections

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